kevin tsolakoy

exelent tutorial

Ashok Kumar Govsa

Best Tutorial for Beginners and it is worked for me. I want to know one advice from you. I want to output text data with html tags. I tried it but it outputs the data without converting the tags. I have used html() method as well but no use. Please guide to print the text data within html tags.

Catalin Popinciuc

<br /> <font size='1'><table class='xdebug-error xe-notice' dir='ltr' border='1' cellspacing='0' cellpadding='1'> <tr><th align='left' bgcolor='#f57900' colspan="5"><span style='background-color: #cc0000; color: #fce94f; font-size: x-large;'>( ! )</span> Notice: Use of undefined constant locatie_student – assumed 'locatie_student' in C:UsersCatalinDesktop5UwAmpwwwajaxname.php on line <i>6</i></th></tr> <tr><th align='left' bgcolor='#e9b96e' colspan='5'>Call Stack</th></tr> <tr><th align='center' bgcolor='#eeeeec'>#</th><th align='left' bgcolor='#eeeeec'>Time</th><th align='left' bgcolor='#eeeeec'>Memory</th><th align='left' bgcolor='#eeeeec'>Function</th><th align='left' bgcolor='#eeeeec'>Location</th></tr> <tr><td bgcolor='#eeeeec' align='center'>1</td><td bgcolor='#eeeeec' align='center'>0.0007</td><td bgcolor='#eeeeec' align='right'>133096</td><td bgcolor='#eeeeec'>{main}( )</td><td title='C:UsersCatalinDesktop5UwAmpwwwajaxname.php' bgcolor='#eeeeec'>…name.php<b>:</b>0</td></tr> </table></font> Suceava<br /> <font size='1'><table class='xdebug-error xe-notice' dir='ltr' border='1' cellspacing='0' cellpadding='1'> <tr><th align='left' bgcolor='#f57900' colspan="5"><span style='background-color: #cc0000; color: #fce94f; font-size: x-large;'>( ! )</span> Notice: Use of undefined constant – assumed '' in C:UsersCatalinDesktop5UwAmpwwwajaxname.php on line <i>8</i></th></tr> <tr><th align='left' bgcolor='#e9b96e' colspan='5'>Call Stack</th></tr> <tr><th align='center' bgcolor='#eeeeec'>#</th><th align='left' bgcolor='#eeeeec'>Time</th><th align='left' bgcolor='#eeeeec'>Memory</th><th align='left' bgcolor='#eeeeec'>Function</th><th align='left' bgcolor='#eeeeec'>Location</th></tr> <tr><td bgcolor='#eeeeec' align='center'>1</td><td bgcolor='#eeeeec' align='center'>0.0007</td><td bgcolor='#eeeeec' align='right'>133096</td><td bgcolor='#eeeeec'>{main}( )</td><td title='C:UsersCatalinDesktop5UwAmpwwwajaxname.php' bgcolor='#eeeeec'>…name.php<b>:</b>0</td></tr> </table></font>…..

What?!

Angel Jean Banez

where does he get global.js? newbie here

Visha

Help plz, im getting this error 🙁

<br /> <b>Warning</b>: mysql_num_rows() expects parameter 1 to be resource, boolean given in <b>C:xampphtdocspuremediaajaxcountry.php</b> on line <b>11</b><br /> <br /> <b>Warning</b>: mysql_error() expects at most 1 parameter, 3 given in <b>C:xampphtdocspuremediaajaxcountry.php</b> on line <b>11</b><br />

KADER DERK

Simple and awesome tutorial,  I have done this similar tutorial using just php and MySQL, I did not include ajax.. Is it secure that way?   but the way I don't have lots experience..

samuel Exaud

i like that

Ici Aidan

I want to do like this but without button. I create a form. If I insert id from table product in text box, all information from table product will show up automatically in textbox product name, textbox product price. Then I can add more than one product in that form without submit it more than one time.

Master Knot See

how do you make the table in phpmyadmin 🙁

chung Noel

mysqli have more and more people using it now, Code Course please add the mysqli below to your description to save the time of others. Thanks for the video.
connect.php:
<?php
$user="root";
$password="";
$dbName="db_name";
$con=mysqli_connect("localhost",$user,$password,$dbName);
name.php
<?php
if (isset($_POST['name']) === true && empty($_POST['name']) === false) {
require '../db/connect.php';
$result = mysqli_query($con,"SELECT country FROM namecountry WHERE name = '{$_POST['name']}'");
$row=mysqli_fetch_assoc($result);
echo (mysqli_num_rows($result)!==0)?$row[country]:"Name not found";
}

Dan Kardell

Great job. I wasn't able to get my JQUERY to work unless I started it off with

$(document).ready(function(){
$('input#name-submit').on('click', function() {

Cowie Tan

Appreciate this vid! Very awesome.

Can someone explain what I should do if I were to get an image file name from the MySQL table and display the image?
Would it be an alteration in global.js :
$('div#name-data').text(data);

Or should the change happen in name.php?

Joseph John

Warning : mysql_num_row() expect parameter 1 to be resource boolean given

mysql_result()
expect parameter 1 to be resource boolean given

help?

alvin wong

the database connection and retrieval don't appear to apply anymore as i received a kinda obselute message. I got it working by using mysqli_connect, mysqli_query, and mysqli_fetch_assoc. I'm on WAMP server.

Mohammed GANNOUNI

Thank you alex <3

Kobid Kunda

sir i m getting this erroe

"<br /> <b>Parse error</b>: syntax error, unexpected 'location' (T_STRING) in <b>E:xampphtdocsaajaxname.php</b> on line <b>10</b><br />"
what wrong im doing i have exactly copied everything correctly

Hicky Klaveren

Very nice. Thanks!

jonathan casanueva willumsen

awesome tut, but ur too fast!

Diego Moreno

Excelent Tutorial….!!
How can data be in a table?
data=2DiegoMorenoNov20
all data print in a line but I want to print into a table like this
<tbody>
<tr>
<td>2</td>
<td>Diego</td>
<td>Moreno</td>
<td>Nov</td>
<td>20</td>
</tr>
 </tbody>

 please help me.. .@Codecourse

Duo Maxwell

thank you, you helped me sort things out a lot. !! ill sub and like

Isaac Rosario Durán

How can i show records in html tables without refresh the page when there are new records in the data base?
I have a project that gets data from the database but if i go into the project in another computer and insert something on it, i need to reload the page to see the new records in my browser, i want to know how can i make the mysql query with ajax to load the new records without refresh!

Sachin Kumar

This is very useful video tutorial, thanks so much